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The initial population of a town is 3600​, and it grows with a doubling time of 10 years. What will the population be in 8 ​years?

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Verdec

If is doubles in 10 years, then you should divide 2 by 10 to get the yearly growth rate equaling 1/5. Multiply 1/5 by 8 equals 8/5= 1 3/5. multiply that number by 3600, giving you 5,760.

The population after 8 ​years is 6268.

What is the exponential growth function?

Exponential growth occurs when the growth rate of the value of a mathematical function is proportional to the function’s current value, resulting in its growth with time being an exponential function.

The initial population of a town is 3600​, and it grows with a doubling time of 10 years.

The exponential growth function can be written as;

\(P(t) = 3600 (2)^{8/10}\\\\P(t)= 3600 \times 2^{0.8}\\\\P(t)= 3600 \times 1.74\\\\P(t)=6268\)

Hence, the population after 8 ​years is 6268.

Learn more about exponential growth function here;

https://brainly.com/question/20598422

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