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23 grams of sodium reacted with 35.5g of chlorine. Calculate the mass of the sodium chloride compound formed.


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Verified Answer :

dexteright02

Molar Masses:

 
MM of Na+ = 23 g / mol

MM of Cl- = 35.5 g / mol

 
Initially we must calculate the number of moles of each participant of the reaction, ie, sodium Na + and chlorine Cl-:
 
→ Number of moles of Na +

 
\(n = \frac{m}{MM}\)
\(n = \frac{23}{23}\)
n = 1 mol

 
→ Number of mols of Cl-

 
\(n = \frac{m}{MM}\)
\(n = \frac{35.5}{35.5}\)
n = 1 mol

 
Reaction:

 
Na + + Cl- -----------> NaCl

 
1 mole Na + ------------------ 1 mole NaCl

1 mole of Na + -------------- y

y = 1 mol of NaCl are produced

 
NaCl Molar Mass = 23 + 35.5 = 58.5 g / mol

 
1 mole of NaCl ---------------- 58.5 g

1 mol ----------------------- m


m = 58.5 grams of NaCl

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