Answer:
Average velocity, v = 433 mph
Explanation:
Given that,
Distance covered by airplane from Phoenix, Arizona, to Atlanta, Georgia, d = 1,592 miles
Time taken, t = 3.68 hours
To find,
The average velocity of the airplane.
Solution,
Let v is the average velocity of the airplane. It is equal to the total distance covered divided by total time taken. Its expression is given by :
\(v=\dfrac{d}{t}\)
\(v=\dfrac{1592\ miles}{3.68\ hours}\)
v = 432.608 mph
or
v = 433 mph
So, the average speed of the airplane is 433 miles per hour.
