Solving:
\(\left \{ {{4x-6y=10\:(I)} \atop {3x+6y=4\:(II)}} \right.\)
\(\left \{ {{4x-\diagup\!\!\!\!\!6y=10} \atop {3x+\diagup\!\!\!\!\!6y=4}} \right.\)
\(\left \{ {{4x=10} \atop {3x=4}} \right.\)
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\(7x = 14\)
\(x = \frac{14}{7}\)
\(\boxed{\boxed{x = 2}}\end{array}}\qquad\quad\checkmark\)
Now replace the found value of "x" in equation (II) to find the value of "y"
\(3x+6y=4\:(II)\)
\(3*(2) + 6y = 4\)
\(6 + 6y = 4\)
\(6y = 4 - 6\)
\(6y = - 2\)
\(y = \frac{-2}{6} \frac{\div2}{\div2} \to \boxed{\boxed{y = \frac{-1}{3}}} \end{array}}\qquad\quad\checkmark\)
Answer:
x = 2
y = - 1/3
