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Which equation would best help solve the following problem?


Maria releases a javelin 1.5 meters above the ground with an initial vertical velocity of 22 meters per second. How long will it take the javelin to hit the ground?



–4.9t^2 + 22t + 1.5 = 0



–16t^2 + 22t + 1.5 = 0



–4.9t^2+ 22t = 1.5



–4.9t^2 + 1.5t + 22 = 0

Verified Answer :

it is the first equation - the -4.9 comes form the acceleration of gravity = 9.8 m s-2
The + 1.5 from the 1 5 metres above the ground from which she throws the javelin

Answer:

Option first is  correct!

Step-by-step explanation:

When an object is thrown above the ground then equation in terms of time (t)

is given by

 \(-\frac{1}{2} gt^2+vt+h=0\)

where g is  acceleration due gravity  and v is the initial velocity and h is height above the ground  at which it is thrown

since here height and speed is given in MKS system

therefore value of  g is also in meter second

that is g = 9.8\(ms^-2\)

so equation is given by

\(-4.9t^2+22t+1.5 =0\) since half of g is 9.8 divided by 2 gives 4.9