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Suppose the vector describing the location of a car moving in a straight line is given by d=<15t, -36t>, where the distance is in miles and the time 't' is in hours. To the nearest minute, how long will it take for the car to move 24 miles?

Verified Answer :

apply the distance formula
\(d= \sqrt{ (x_2 - x_1)^2 +(y_2-y_1)^2}\)

except if you use the starting point of (0,0), its essentially an application of pythagorean theorem

x2 would be 15t
y2 would be -36
t

and d would be 24

writing it all out would be
24^2= (15t)^2 + (-36t)^2

in which case, just expand, and solve for t

any questions?