Suppose that the Toronto Blue Jays face the

New York Yankees in the division final. In

this best-of-five series, the winner is the first

team to win three games. The games are

played in Toronto and in New York, with

Toronto hosting the first, second, and if

needed, fifth games. The consensus among

experts is that Toronto has a 65% chance of

winning at home and a 40% chance of

winning in New York.

AConstruct a tree diagram to illustrate all

the possible outcomes.

BWhat is the chance of Toronto winning

in three straight games?

I have attached my tree diagram. Pls. see attachment. Assuming that Toronto Blue Jays won the first 3 sets:

W W W = 65% 65% 40% = 16.90%

Other probabilities:
W W L = 65% 65% 60% = 25.35%
W L W = 65% 35% 40% = 9.10%
W L L = 65% 35% 60% = 13.65%
L W W = 35% 65% 40% = 9.10%
L W L = 35% 65% 60% = 13.65%
L L W = 35% 35% 40% = 4.90%
L L L = 35% 35% 60% = 7.35%

These probabilities are correct because when we all add up the probabilities, the sum is 100%

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