Answer:
Molar mass of \(BF_{3}\) is 67.805 g.
Explanation:
Molar mass of a molecule is the sum of atomic masses of all constituting atoms.
In \(BF_{3}\), there are one boron atom and three fluorine atoms.
Atomic masses of boron and fluorine are 10.811 g and 18.998 g respectively.
So molar mass of \(BF_{3}\) = (10.811 g)+(\(3\times\)18.998 g) = 67.805 g
