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edrake1 edrake1
  • 17-02-2015
  • Mathematics
Answered

Solve the quadratic equation y^2-5y=-4 by factoring.

Verified Answer :

konrad509
konrad509 konrad509
  • 17-02-2015

\(y^2-5y=-4\\ y^2-5y+4=0\\ y^2-y-4y+4=0\\ y(y-1)+4(y-1)=0\\ (y+4)(y-1)=0\\ y=-4 \vee y=1\)

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