Answer: 16
Step-by-step explanation:
Given: A jar contains \(24\) pennies. The pennies are taken out and divided into \(2\) piles. If the larger pile contains twice as many pennies as the smaller one.
To Find: how many pennies are in the larger pile.
Solution:
Total number of pennies in the jar \(=24\)
let the number of pennies in bigger pile \(=\text{x}\)
let the number of pennies in smaller pile \(=\text{y}\)
Now,
\(\text{x}+\text{y}=24\)
as \(\text{x}=2\text{y}\)
\(2\text{y}+\text{y}=24\)
\(3\text{y}=24\)
\(\text{y}=8\)
\(\text{x}=2\text{y}\)
\(\text{x}=2\times8\)
\(\text{x}=16\)
Hence there are \(16\) pennies in larger pile.
