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24 POINTS!!!!!!!!!!!!!!

A semicircle is attached to the side of a rectangle as shown.


What is the best approximation for the area of this figure?


Use 3.14 to approximate pi.


The area is ________

24 POINTS!!!!!!!!!!!!!! A semicircle is attached to the side of a rectangle as shown. What is the best approximation for the area of this figure? Use 3.14 to ap class=

Verified Answer :

Area of the figure = Area of rectangle + area of semi-circle

Area of rectangle = a b = 6 2 = 12 m²

Area of the semi-circle = πr²/2 = 3.14 * (1.5)²/2
A = 3.53

Area of figure = 12 + 3.53 = 15.53 m²

In short, Your Final Answer would be: 15.53 m²

Hope this helps!

calculista

Answer:

\(15.5\ m^{2}\)

Step-by-step explanation:

we know that

The area of the figure is equal to the area of a rectangle plus the area of semicircle

Step 1

Find the area of the rectangle

The area of the rectangle is equal to

\(A=bh\)

we have

\(b=6\ m\)

\(h=2\ m\)

substitute

\(A=6*2=12\ m^{2}\)

Step 2

Find the area of semicircle

The area of semicircle is equal to

\(A=\frac{1}{2}\pi r^{2}\)

we have

\(r=3/2=1.5\ m\)

substitute

\(A=\frac{1}{2}(3.14)(1.5^{2})=3.5\ m^{2}\)

Step 3

Find the area of the figure

\(12\ m^{2}+3.5\ m^{2}=15.5\ m^{2}\)


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