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Which equation is the inverse of 5y+4 = (x+3)^2 + 1/2

AY=1/5 x^2 + 6/5 x + 11/10

BY=3 plus or minus square root 5x + 7/2

C-5y -4 = -(x+3)^2 -1/2

DY= -3 plus or minus square root 5x + 7/2

Verified Answer :

Answer:

Option D is correct.

Step-by-step explanation:

Given equation is \(5y+4=(x+3)^2+\frac{1}{2}\)

We need to find inverse of the function.

Let x be the independent variable or the function is in x variable.

So,

we Simplify the given equation for variable of x.

\(5y+4=(x+3)^2+\frac{1}{2}\)

\(5y+4-\frac{1}{2}=(x+3)^2\)

\(5y+\frac{7}{2}=(x+3)^2\)

\(\pm\sqrt{5y+\frac{7}{2}}=x+3\)

\(x+3=\pm\sqrt{5y+\frac{7}{2}}\)

\(x=-3\pm\sqrt{5y+\frac{7}{2}}\)

Inverse of the given equation = \(-3\pm\sqrt{5y+\frac{7}{2}}\)

Therefore, Option D is correct.