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A ball is hurled in the air such that its horizontal (x) and vertical (y) shifts are given by the functions x(t) = 20t and y(t) = 40t – 5tÆ, where x and y are in meters and the time t is in seconds. What is the ratio of y to x at time t = 5 seconds?

Verified Answer :

kishonwinston

at t = 5:

x(5) = 100
y(5) = 200 - 25
       = 175

\(\frac{y(5)}{x(5)}\) = \(\frac{175}{100}\) = 7/4

lingling522

It would be 4958 divided by 8 aand

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