How would you solve k^2-5k+6=0
k2 + -5k + 6 = 0 6 + -5k + k2 = 0 6 + -5k + k2 = 0 Solving for variable 'k'. Factor a trinomial.(2 + -1k)(3 + -1k) = 02 + -1k = 0k = {2, 3}hoped this helped i skipped some steps so you don't have to wait
k^2-5k+6=0k^2-5k=-6k-2.23k=2.441.23k=2.44k=1.99
