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Verified Answer :

Sofiadecredico

multiply everything in the first parenthasis by everything in the second parentahsis

(s-t)(2s-3t) = 2s²-3st-2st+3t²  then combine like terms

2s²-5st+3t²

Lik3abos5

FOIL:
First
Outter
Inner
Last
s(2s)+(s)(-3t)+(-t)(2s)+(-t)(-3t)
(2s2)+(−3st)+(−2st)+(3t2)==(2s2)+(−3st)+(−2st)+(3t2)=

=2s2−5st+3t2=2s2−5st+3t2.

Answer: (s−t)(2s−3t)=2s2−5st+3t2(s−t)(2s−3t)=2s2−5st+3t2.

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