factorization of x3+8
Answer:
The factor of \(x^{3}+8\) is \((x+2)(x^{2}-2x+4)\)
Step-by-step explanation:
We need to factorise the given expression \(x^{3}+8\)
Re-write the expression \(x^{3}+8\) as:
\(x^{3}+2^{3}\)
Since, \(a^{3}+b^{3}=(a+b)(a^{2}-ab+b^{2})\)
so, here a = x and b = 2
\((x+2)(x^{2}-2x+2^{2})\)
\((x+2)(x^{2}-2x+4)\)
Hence, The factor of \(x^{3}+8\) is \((x+2)(x^{2}-2x+4)\)