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Please help me with this math question?? :)


The measure of each exterior angle of a regular octogon is _____ the measure of each exterior agle of a regular hexagon.

AGreater than
BLess than
CEqual to

Verified Answer :

\(\bf \textit{exterior angle of a regular polygon} \\\\\\ \theta=\cfrac{360}{n}\qquad \begin{cases} \theta=\textit{the angle in degrees}\\ n=\textit{number of sides} \end{cases}\)

now, an OCTAgon, has OCTA=8, sides
an HEXAgon, has HEXA=6, sides

check what their external angles are, and compare :)

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