(4,-2) m=-1 how can you graph this
(4,-2) m=-1 how can you graph this
ok, so assuming you know what the slope of -1 looks like
a bit like \ except more diagonal
you look for point (4,-2), then you draw the -1 slope from it
it should cross through points (5,-3) and (3,-1)
Ok, so -1 is m. This is related to point-slope form, y=mx+b. In this formula, m is the slope of the line. You also found a point (4,-2). This means that this is a definite point on the graph. So, place this point on the graph at x=4 and y=-2. Then, because the slope is -1, go left 1 up 1 and then right 1 down 1 from this point and it will give you the graph of this equation. The graph will look like this. Notice it passes through the point (4,-2). Hope this helps! :D