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(GEOMETRY, SERIOUS HELP! PLS)

The diagonal of rectangle ABCD measures 2 inches in length.


What is the length of line segment AB?



1 inch


(Sqr root) 3 inches


4 inches


(Sqr root) 4/3 inches

(GEOMETRY, SERIOUS HELP! PLS) The diagonal of rectangle ABCD measures 2 inches in length. What is the length of line segment AB? 1 inch (Sqr root) 3 inches 4 in class=

Verified Answer :

For this case we have the following trigonometric relationship:

\(cos(30)=\frac{CD}{2}\)

From here, we clear the value of the CD segment:

\(CD = 2cos(30)\)

\(CD = 2\frac{\sqrt{3}}{2}\)

\(CD = \sqrt{3}\)

Then, since the figure is a rectangle, then it follows that:

\(AB = CD = \sqrt{3}\)

Answer:

the length of line segment AB is:

\(AB = \sqrt{3}\)

option 2

The length of the side CD and AB is √3

What are Trigonometric functions?

\(Sin \theta=\dfrac{Perpendicular}{Hypotenuse}\)

\(Cos \theta=\dfrac{Base}{Hypotenuse}\)

\(Tan \theta=\dfrac{Perpendicular}{Base}\)

where perpendicular is the side of the triangle which is opposite to the angle, and the hypotenuse is the longest side of the triangle which is opposite to the 90° angle.

Given to us

  • BD = 2 inches
  • ∠CBD = 60°
  • ∠CDB = 30°

In ΔBCD,

For ∠B

\(Sin \theta=\dfrac{Perpendicular}{Hypotenuse}\)

\(Sin(\angle B)=\dfrac{CD}{BD}\\\\Sin(60^o)=\dfrac{CD}{2}\\\\CD = 2 \times Sin(60^o)\\\\ CD = 2 \times \dfrac{\sqrt3}{2}\\\\CD = \sqrt3\)

Thus, the length of the side CD is √3.

Length of Side AB

As it is already given that the figure ABCD is a rectangle the length of side AB is equal to CD.

AB = CD = √3

Hence, the length of the side CD and AB is √3.

Learn more about Trigonometric functions:

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