Answer:
\(y=2sin(2(x-\pi))\)
Step-by-step explanation:
The general equation of a sine function can be written as:
\(y=(Amplitude)sin({\frac{2\pi}{period})(x-shift)\)
Now, we are given that the amplitude is \(2\) and period is of \(\pi\) with a horizontal shift of \(\pi\) units, thus the general equation becomes
\(y=2sin(\frac{2\pi}{\pi})(x-\pi)\)
\(y=2sin(2(x-\pi))\)
which is the required general equation of a sine function.
