Answer: The correct option is (B) -172.
Step-by-step explanation: We are given to find the 32nd term of the arithmetic sequence where the 1st term and 13th term are
\(a_1=14,~~~a_{13}=-58.\)
We know that
the n-th term of an arithmetic sequence with first term \(a_1\) and common difference \(d\) is given by
\(a_n=a_1+(n-1)d.\)
According to the given information, we have
\(a_1=14,\)
and
\(a_{13}=-58\\\\\Rightarrow a_1+(13-1)d=-58\\\\\Rightarrow 14+12d=-58\\\\\Rightarrow 12d=-58-14\\\\\Rightarrow 12d=-72\\\\\Rightarrow d=-6.\)
Therefore, the 32nd term will be
\(a_{32}=a_1+(32-1)d=14+31\times(-6)=14-186=-172.\)
Thus, the 32nd term is -172.
Option (B) is correct.
