Let R be the region between the graph of y=e^-2x and the x-axis for x greater than or = to 3. The area of R is?
When you substitute a 3 you get 1/2e∧(-6) and when you substitute a t it just goes to 0
Answer
1/2e(-6)
The area between the graph of \(y=e^{-2x}\) and the x-axis for x greater than or equal to 3 will be \(\dfrac{e^{-6}}{2}\) and it can be determine by doing the integration of the given function.
Given :
\(y=e^{-2x}\)
The area between the graph of \(y=e^{-2x}\) and the x-axis for x greater than or equal to 3 will be:
\(\rm Area = \int\limits^\infty_3 {e^{-2x}} \, dx\)
\(\rm Area = 0-(-\dfrac{1}{2e^{6}})\)
\(\rm Area = \dfrac{e^{-6}}{2}\)
The area of region R is \(e^{-6}\div 2\).
For more information, refer the link given below:
https://brainly.com/question/9658189