solve for x: (With steps pls): x³eˣ-4xeˣ=0
When e^x=0 there is not an x value because there is a horizontal asymptote x=0.
You can solve it with natural logs:x³eˣ-4xeˣ=0x³eˣ=4xeˣnatural log both sideslnx³eˣ=ln4xeˣDistribute the ln, bring the x exponent down and cancel out the ln e combinationslnx³xlne=ln4xxlnexlnx³=xln4x x's and ln's cancel outx³=4xx=2
