Find the zeros. g(x)=(x^2+4x-12)(x-3)
g(x)=(x^2+4x-12)(x-3) =(x+6)(x-2)(x-3) =x+6 = 0 -6 -6 x=-6 x-2 = 0 +2 +2 x=2 x-3 = 0 +3 +3 x=3The zeros are {-6, 2, 3}
