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Which atom attracts electrons more strongly?

cesium (Cs)

bromine (Br)

Which atom loses an electron more readily?

sodium (Na)

chlorine (Cl)

Verified Answer :

tzarplatypus

Bromine attracts electrons more strongly. Cesium is In fact the least electro negative element.

Sodium is more likely to lose an electron because is is less electro negative. Strong electronegativity make the element want more electrons. Sodium has loose electrons with a lower electronegativity so it gives it up easier.

Explanation:

1.    Cesium (Cs) is a group 1 element and it has electronic configuration \([Xe] 6s^{1}\).

On the other hand, bromine is a group 7 element and it has electronic configuration \([Ar] 3d^{10}4s^{2}40^{5}\).

Since, Cs is a metal so it will readily lose 1 electron but bromine being a non-metal needs 1 electron to completely fill its orbital.

Hence, bromine atom will attract electrons more strongly.

2.   Sodium (Na) is a a group 1 element and it has electronic configuration \(1s^{2}2s^{2}2p^{6}3s^{1}\).

Whereas, chlorine is a group 7 element and it has electronic configuration \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{5}\).

So, sodium is a metal hence, it readily loses its one electron and chlorine being a non-metal will attract one electron in order to completely fill its orbital.

Thus, we can conclude that sodium (Na) atom loses an electron more readily.

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