Answer" The average force on the wall be equal to 0.5 N.
Explanation:
To calculate the average force on the wall, we use the following equation:
\(Ft=m\Delta v\\\\F=\frac{m(v_2-v_1)}{t}\)
where,
F = average force = ?N
m = mass of the ball = 0.05kg
\(v_1\) = Initial velocity of the ball = -10m/s (negative sign because the ball rebounds)
\(v_2\) = Final velocity of the ball = 10m/s
t = time taken by the ball = 2s
Putting values in above equation, we get:
\(F=\frac{0.05kg[10-(-10)]m/s}{2s}\\\\F=\frac{0.05kg(20m/s)}{2s}\\\\F=0.5kgm/s^2=0.5N\)
Hence, the average force on the wall will be equal to 0.5N.