Data:
STP means
T = 0ºC or 273 K
P = 1 atm
V = 283 mL = 0.283 L
R = 0.082 atmL/molK
Formula: Find "n" moles
\(n = \frac{P*V}{R*T}\)
Solving:
\(n = \frac{P*V}{R*T}\)
\(n = \frac{1*0.283}{0.082*273}\)
\(n = \frac{0.283}{22.3}\)
\(\boxed{n \approx 0.01\;mol}\)
Now find the mass
Knowing that the molar mass of \(Cl_{2}\) = 71 g / mol
\(0.01\:\diagup\!\!\!\!\!\!mol* \frac{71\:grams}{1\:\diagup\!\!\!\!\!\!mol} = \boxed{\boxed{0.71\:grams\: Cl_{2} }}\end{array}}\qquad\quad\checkmark\)
