A compound is found to contain only 24.5 g nitrogen and 70.0 g oxygen. what is the compounds empirical formula.
to solve the emprical formula, convert the mass to moles.
moles N = 24.5 g ( 1 mole / 14 g) = 1.75
moles O = 70 g ( 1 mole / 16 g ) = 4.325
then divide the number of moles by the lowest to get the coefficient of each element
N = 1.75 / 1.75 = 1
O = 4.325 / 1.75 = 2.5
so the empirical formula NO5/2
or N2O5
The whole number ratio of the atoms of the compounds is called the empirical formula. The empirical formula containing nitrogen and oxygen is \(\rm N_{2}O_{5}.\)
The empirical formula is the representation formula of the atoms or the molecules of the compound. It is given with the help of the mass and the moles of the atoms.
Calculate moles of nitrogen:
\(\begin{aligned} \rm moles &= \rm \dfrac{mass}{\rm molar\; mass}\\\\&= \dfrac{24.5}{14}\\\\&= 1.75\;\rm moles\end{aligned}\)
Calculate moles of oxygen:
\(\begin{aligned} \rm moles &= \rm \dfrac{mass}{\rm molar\; mass}\\\\&= \dfrac{70}{16}\\\\&= 4.375\;\rm moles\end{aligned}\)
When dividing the moles with the smallest mole number the ratio of the carbon and oxygen = 1:2.5 or 2:5. The empirical formula is \(\rm N_{2}O_{5}.\)
Therefore, the empirical formula is \(\rm N_{2}O_{5}.\)
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