Answer:
81.8%
Step-by-step explanation:
Mean = \(\mu = 40\)
Standard deviation = \(\sigma = 5\)
Now we are supposed to find out what percent of the numbers fall between 35 and 50
\(z = \frac{x-\mu}{\sigma}\)
Substitute the values
\(z = \frac{x-40}{5}\)
Now for P(35<x<50)
Substitute x = 35
\(z = \frac{35-40}{5}\)
\(z =-1\)
Substitute x = 50
\(z = \frac{50-40}{5}\)
\(z =2\)
So, P(-1<z<2)
P(z<2)-P(z<-1)
=0.9772-0.1587
=0.8185
= \(0.818 \times 100\)
=81.8%
Hence 81.8% percent of the numbers fall between 35 and 50
