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Verified Answer :

-log (1.2x10^-2) = 1.92 so C

Answer: The pH of the solution is 1.92

Explanation:

To calculate the pH of the solution, we use the equation:

\(pH=-\log[H^+]\)

We are given:

Hydrochloric acid is a monoprotic acid and it dissociates 1 mole of hydrogen ions. So, the concentration of hydrogen ions is \(1.20\times 10^{-2}M\)

\([H^+]=1.20\times 10^{-2}M\)

Putting values in above equation, we get:

\(pH=-\log(1.20\times 10^{-2})\\\\pH=1.92\)

Hence, the pH of the solution is 1.92