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A mixture contains forty ounces of glycol and water and is ten percent glycol. If the mixture is to be strengthened to twenty-five percent, how much glycol is to be added?


4 oz

8 oz

10 oz

Verified Answer :

if we add 8 oz of glycol to the 40 oz mixture we have 48 oz of mixture and 4+8 = 12 oz glycol
 12 / 48  = 1/4   = 25 % glycol 

the answer is 8 oz

10(40) + x = .25(x + 40)
 
4 + x = .25x + 10
 
x - .25x = 10 - 4
 
.75x = 6
x =
x = 8 oz of glycol required

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