Web Analytics

Verified Answer :

\(x^2+y^2-4x=0\)
\(r^2\cos^2\theta+r^2\sin^2\theta-4r\cos\theta=0\)
\(r^2(\cos^2\theta+\sin^2\theta)-4r\cos\theta=0\)
\(r^2=4r\cos\theta\)
\(r=4\cos\theta\)

Conversion of \(${{x}^{2}}+{{y}^{2}}-4x=0$\) is circle with centre at \($\left( 2,0 \right)$\) and radius \($r=2$\).

What is circle equation?

A circle is a collection of all points in a plane that are evenly spaced. The fixed point is known as the circle's center.

So, the standard equation of a circle is given by:

\(${{\left( x-a \right)}^{2}}+{{\left( y-b \right)}^{2}}={{r}^{2}}$\)

Where \((a,b)\)  is the coordinates of center of the circle and \(r\) is the radius.

Rewrite \(${{x}^{2}}+{{y}^{2}}-4x=0$\) in the form of the standard circle equation.

So,

\(${{x}^{2}}-4x+{{y}^{2}}=0$\)

Add \($4$\) both sides of the given equation.

\(${{x}^{2}}-4x+4+{{y}^{2}}=0+4$\)

\(${{\left( x-2 \right)}^{2}}+{{y}^{2}}=4$\)

\(${{\left( x-2 \right)}^{2}}+{{\left( y-0 \right)}^{2}}={{\left( 2 \right)}^{2}}$\)

Therefore, the circle properties are,

\($\left( a,b \right)=\left( 2,0 \right)$\)

and \(r=2\)

Learn more about circle of polar coordinates here

https://brainly.com/question/12809711

#SPJ2