Answer:
3.71 m/s^2
Explanation:
The acceleration of gravity on the surface of a planet can be found by using the following formula:
\(g=\frac{GM}{r^2}\)
where
\(G=6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2}\) is the gravitational constant
\(M=6.39\cdot 10^{23} kg\) is the mass of the planet (in this case, Mars)
\(r=3.39\cdot 10^6 m\) is the radius of the planet (in this case, Mars)
Substituting the numbers into the formula, we find
\(g=\frac{(6.67\cdot 10^{-11})(6.39\cdot 10^{23} kg)}{(3.39\cdot 10^6 m)^2}=3.71 m/s^2\)
