I'm going to use "x" because the program lets me put in exponents.
4\(x^{2}\)-6x+2+3\(x^{2}\)-1 7\(x^{2}\)-6a-1 Then factor (7x+1)(x-1) Set each to 0 to solve for x x-1=0 is x=1 7x+1=0 7x=-1 x=\(\frac{-1}{7}\) So your answers are x=1 and x=\(\frac{-1}{7}\)
