Find the area of each parallelogram plz help
Find the area of each parallelogram plz help
Answer: The area of the parallelogram is:
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\(\frac{9393}{8}\) in² = 1174 ⅛ in² = 1174.125 in² .
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Explanation:
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Area of a parallelogram:
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A = base height = b h ;
From the figure (from the actual "question"):
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b = 50.5 in.
h = 23.25 in.
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Method 1) A = b h =
= (50.5 in) (23.25 in) = 1174.125 in² ; or, write as: 1174 ⅛ .
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Method 2) A = b h =
= (50 ½ in) (23 ¼ in) =
= (\(\frac{101}{2}\) in) (\(\frac{93}{4}\) in) ;
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Note: "50 ½ " = [(502) + 1 ] / 2 = \(\frac{101}{2}\) ;
Note: "23 ¼ " = [(234) + 1 ] / 4 = \(\frac{93}{4}\) ;
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→ A = (\(\frac{101}{2}\) in) (\(\frac{93}{4}\) in) ;
→ A = \(\frac{(101*93)}{(2*4)}\) in² = \(\frac{9393}{8}\) in² ;
→ A = (9393/8) in² =
→ A = \(\frac{9393}{8}\) in² = 1174 ⅛ in² = 1174.125 in² .
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