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In ΔDEF shown below, segment DG is an altitude:


Triangle DEF with segment DG drawn from vertex D and intersecting side EF.


Which of the following is a step towards proving the similarity of triangles ΔDEF and ΔGED? (6 points)



Segment EF is a hypotenuse.


Angle E is congruent to itself.


Segment ED is shorter than segment EF.


Segment EF is intersected by segment DG.

Verified Answer :

taskmasters

I found the corresponding image.

The step towards proving the similarity of triangles DEF and GED is:

ANGLE E IS CONGRUENT TO ITSELF.

ΔDEF is a right triangle. Its hypotenuse is EF, its long leg is DF, its short leg is DE.
ΔGED is also a right triangle. Its hypotenuse is DE, its long leg is DG, its short leg is GE.

Only Angle E is in both triangles and its measure remains the same.

View image taskmasters

Answer:

option 2 Angle E is congruent to itself.

Step-by-step explanation:

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