Data:
pH = 5.2
[H+] = ?
Knowing that: (Equation to find the pH of a solution)
\(pH = -log[H+]\)
Solving:
\(pH = -log[H+]\)
\(5.2 = - log [H+]\)
Knowing that the exponential is the opposite operation of the logarithm, then we have:
\([H+] = 10^{-5.2}\)
\(\boxed{\boxed{[H+] = 6.30*10^{-6}}}\end{array}}\qquad\quad\checkmark\)
