In order to increase the circumference of a circle from 12π cm to 18π cm, by how much must the diameter increase?
Answer: The increase in the diameter is 6 cm.
Step-by-step explanation:
The circumference of a circle with diameter 'd' is given by :
Circumference=\(\pi d\)
Given: The circumference is increased from \(12\pi\ cm\ to\ 18\pi\ cm\)
It implies the increase in the circumference=\(\pi d_2-\pi d_1=18\pi-12\pi\), where \(d_1\) is the previous diameter and \(d_2\)
is the new diameter.
\(\Rightarrow\pi(d_2-d_1)=\pi(18-12)\\\Rightarrow(d_2-d_1)=6\)
Hence, the increase in the diameter= 6 cm
The diameter of the circle must increase by 6
The circumference of a circle is calculated as:
\(C = \pi d\)
Given that:
\(C_1 = 12\pi\) --- the initial circumference
\(C_2 = 18\pi\) --- the final circumference
So, we have:
\(\pi d_1 =12\pi\)
\(\pi d_2 =18\pi\)
Where:
\(d_2 = d + d_1\)
So, we have:
\(\pi d_2 = \pi (d + d_1)\)
\(\pi (d + d_1) = 18\pi\)
Subtract \(\pi d_1 =12\pi\) from \(\pi (d + d_1) = 18\pi\)
\(\pi(d + d1 - d1) = 18\pi - 12\pi\)
\(\pi(d) = 6\pi\)
Divide both sides by \(\pi\)
\(d= 6\)
Hence, the diameter must increase by 6
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