Answer:
The correct option is 3. The value of 18 is 1.5 standard deviations away from the mean.
Step-by-step explanation:
It is given that a normal distribution has a mean of 12 and a standard deviation of 4.
\(\mu=12\)
\(\sigma=4\)
We have to find the value of
\(z=\frac{x-\mu}{\sigma}\)
The value of x is 18.
\(z=\frac{18-12}{4}\)
\(z=\frac{6}{4}\)
\(z=1.5\)
The value of z is 1.5, therefore the value of 18 is 1.5 standard deviations away from the mean. Option 3 is correct.
