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The starting materials in a nuclear change have a total mass of 2.3465 × 10–27 kg. After the change, the resulting materials have a mass of 2.3148 × 10–27 kg.

How much energy was released during the change?

Verified Answer :

Answer:

The energy released during the change is \(2.853\times10^{-12}\ J\).

Explanation:

Given that,

Total mass \(m =2.3465\times10^{-27}\ kg\)

After change , the mass of resulting materials

\(m'=2.3148\times10^{-27}\ kg\)

Using the Einstein's mass energy equation

\(E = mc^2\)

The energy released during the change is given by

\(\Delta E= \Delta mc^2\)

Where, \(\Delta m\) is the change of mass in the process

c = speed of light

The change in mass

\(\Delta m=m-m'\)

\(\Delta m=2.3465\times10^{-27}-2.3148\times10^{-27}\)

\(\Delta m= 0.0317\times10^{-27}\ kg\)

We substitute the value into the formula

\(\Delta E = 0.0317\times10^{-27}\times(3\times10^{8})^2\)

\(\Delta E= 2.853\times10^{-12}\ J\)

Hence, The energy released during the change is \(2.853\times10^{-12}\ J\).

idk19816

Answer:

A

Explanation:

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