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Which shows one way to determine the factors of x3 + 11x2 – 3x – 33 by grouping?



x2(x + 11) + 3(x – 11)


x2(x – 11) – 3(x – 11)


x2(x + 11) + 3(x + 11)


x2(x + 11) – 3(x + 11)

Verified Answer :

carlosego

For this case we have the following polynomial:


\(x ^ 3 + 11x ^ 2 - 3x - 33
\)

By grouping terms we have:

\((x ^ 3 + 11x ^ 2) - (3x + 33)
\)

Then, we make a common factor of the terms grouped in each parenthesis.

For the first parenthesis we make a common factor x^2.

For the second parenthesis we do common factor 3.

We have then:


\(x ^ 2 (x + 11) - 3 (x + 11)
\)

Answer:

one way to determine the factors of \(x^3 + 11x^2 - 3x - 33\) by grouping is:

\(x ^ 2 (x + 11) - 3 (x + 11)\)

alexos54

Answer:

one way to determine the factors of  by grouping is:

D

Step-by-step explanation:

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