Note that this force does \(20 \, N \cdot 5.2 \, m = 104 \, J\) of work. Then, by conservation of energy, we have that:
\(\frac{mv^2}{2} = 104 \, J\)
Substituting \(m=22 \, kg\), we see that:
\(11v^2 \, kg = 104 \, J\)
Then, dividing by \(11\) and taking the square root, we see that:
\(v=~3.1 \, m/s\)