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A jet plane traveling at 450 mph overtakes a propeller plane traveling at 250 mph that had a 3​-hour head start. How far from the starting point are the​ planes?

Verified Answer :

it's suppose to add 450mph+250mph=700 then divide 3 hours=233.3

aachen

Answer:

1687.5 miles

Step-by-step explanation:

Given: A jet plane traveling at 450 mph overtakes a propeller plane traveling at 250 mph that had a 3​-hour head start.

To Find: How far from the starting point are the​ planes

Solution:

Speed of jet plane = \(450\) \(\text{mph}\)

speed of Propeller plane = \(250\) \(\text{mph}\)

Distance travelled by propeller plane in 3 hours head start = \(\text{speed of propeller plane}\times\text{time}\)

                                              = \(250\times3\) = \(750\) \(\text{miles}\)

Distance to be travelled by jet plane to overtake propeller plane =  \(\text{distance between both planes}\)

                                                       \(750\)  \(\text{miles}\)

Relative speed of both planes = \(\text{Speed of jet plane}-\text{speed of propeller plane}\)

                                                    \(450-250=200\) \(\text{mph}\)

Time taken by jet plane to overtake propeller plane =  

                                         \(\frac{\text{Distance between both planes}}{\text{relative speeds of planes}}\)

                                                    \(\frac{750}{200}=\frac{15}{4}\) \(\text{hours}\)

total distance travelled by plane = \(\text{Time taken by jet plane to overtake propeller plane}\times\text{speed of jet plane }\)

                                                       \(450\times\frac{15}{4}=1687.5\) \(\text{miles}\)

planes are \(1687.5\) \(\text{miles}\) far from starting point.