Answer:The new volume when 0.40 moles of gas are added to the balloon is 8 L.
Explanation:
Initial moles of gas \(n_1\) = 0.10 moles
initial volume of the balloon, \(V_1\) = 2.0 L
Final moles of gas \(n_2\) = 0.40 moles
Final volume of the balloon, \(V_2\) = 2.0 L
Avogadro Law:\(\frac{n_1}{V_1}=\frac{n_2}{V_2}\)
\(V_2=\frac{n_2\times V_1}{n_1}=\frac{0.40 mol\times 2.0L}{0.10 mol}=8.0 L\)
The new volume when 0.40 moles of gas are added to the balloon is 8 L.
