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Given the following chemical equation, how many moles of carbon are necessary to react with 5.52 moles of SO2?5C(s) + 2SO2 (g) --> CS2 (l) + 4CO (g)

5.52 moles SO2

2.00 moles SO2

13.8 moles SO2

11.0 moles SO2

Verified Answer :

The ratio between C and SO2 is 5:2 So....
take 5.52 * 5 / 2 = 13.8 mol C needed

Answer : The moles of carbon needed will be, 13.8 moles

Explanation : Given,

Moles of \(SO_2\) = 5.52 mole

Now we have to calculate to moles of carbon.

The given balanced chemical reaction is,

\(5C(s)+2SO_2(g)\rightarrow CS_2(l)+4CO(g)\)

From the balanced chemical reaction, we conclude that

As, 2 mole of \(SO_2\) react to give 5 moles of carbon

So, 5.52 mole of \(SO_2\) react to give \(\frac{5}{2}\times 5.52=13.8\) moles of carbon

Therefore, the moles of carbon needed will be, 13.8 moles

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