Answer:
D. It is not a function.
Step-by-step explanation:
Radius of given circle = 4 units
Center = (0,0)
Equation of circle : \((x-h)^2+(y-k)^2 =r^2\)
where (h,k) is the center
So, equation of given circle = \(x^2+y^2 =4^2\)
Substitute x = -1
\((-1)^2+y^2 =4^2\)
\(1+y^2 =16\)
\(y=\sqrt{15}\)
\(y=\pm 3.872\)
So, since at one value of x we are getting the two values of y .
A function is a relation that for each input, there is only one output.
So, It is not a function.
Hence Option D is true.
