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Verified Answer :

1/x+x/(x+2)=1

take LCM
\((x+2)+x^2/(x(x+2)=1\)
x+2+x^2=x(x+2)
\(x^2+x+2=x^2+2x\)
x=2
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2)\(1/(x-3)+1/(x+5)=x+1/x-3\)

\(x+5+x-3/(x+1)(x-3)=x+1/x-3\)
\(2x+2=(x+1)(x+5)\)
\(2x+2=x^2+5x+x+5\)
\(x^2+4x+3=0\)
\(x^2+3x+x+3=0\)
(x+1)(x+3)=0
x= - 1, x= - 3

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3)\(3x/x^2+2x-8=1/x-2+x/x+4\)

after solving both side u will get

\(3x=x+4+x-2\)
3x=2x+2

x=2

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\(1/x^2-1 =2/x^2+x-2\)

1/(x-1)(x+1)=2/(x-1)(x+2)
u will get same will cross out each other
1/(x+1)=2/(x+2)
(x+2)=2(x+1)
x+2=2x+2
x=0