The volume of a cylinder with a radius r and a height h:
\(V_1=\pi r^2h\)
The volume of a cone with a radius r and a height h:
\(V_2=\dfrac{1}{3}\pi r^2h\)
Therefore
\(V_2=\dfrac{1}{3}V_1\)
We have \(V_1=32.25\ in^3\)
Substitute:
\(V_2=\dfrac{1}{3}\cdot32.25=10.75\ in^3\)
Answer: The volume of a cone is equal 10.75 in³
