Given the following linear function sketch the graph of the function and find the domain and range. ƒ(x) = -3x + 7
Find the y-intercept (7 because it's in slope-intercept form). That would be (0,7). Plot that point.
Find another point. For example, plug in 1 for x. Then solve for f(x) which would be -3(1) + 7 = 4. That would be (1, 4). Plot that point.
Connect the dots and you have a line.
The domain is (-infinity, infinity) because it's an infinite line.
The range is the same because it's an infinite line.
Answer:
\(\text{Domain: }(-\infty,\infty)\)
\(\text{Range: }(-\infty,\infty)\)
Graph : Attachment
Step-by-step explanation:
Given: \(f(x)=-3x+7\)
We need to graph it and find the domain and range of the function.
Domain: It is input value of x where function is well defined.
\(\text{Domain: }(-\infty,\infty)\)
Range: It is output value of f(x)
\(\text{Range: }(-\infty,\infty)\)
Now we draw the graph of f(x) using table method.
So, first we have to make the table of x and y
Put x=-1 into f(x)
f(-1)=-3(-1)+7 = 3+7 = 10
(-1,10)
Put x=1 into f(x)
f(1)=-3(1)+7 = -3+7 = 4
(1,4)
Put x=0 into f(x)
f(0)=-3(0)+7 = 0+7 =7
(0,7)
x : -1 0 1
f(x) : 10 7 4
Now we plot the points on graph. Please find the attachment for graph.