There are white, blue, and red boats in a marina. Five-sixths of the boats in the marina are white, 2/5 of the remaining boats are blue, and the rest are red. If there are 12 red boats, how many boats are in the marina?
Answer: There are 120 boats in marina.
Step-by-step explanation:
Let x be the total number of boats in the marina.
As per given , Number of white boats = \(\dfrac{5}{6}x[\tex]
Number of blue boats = [tex]\dfrac{2}{5}(x-\dfrac{5}{6}x)=\dfrac{2}{5}(\dfrac{x}{6})=\dfrac{x}{15}[\tex]
Number of red boats = [tex]x-\dfrac{5}{6}x-\dfrac{x}{15}[\tex]
[tex]=x(\dfrac{30-25-2}{30})=x(\dfrac{3}{30})=\dfrac{x}{10}\)
Since , Number of red boats = 12
Therefore, \(\dfrac{x}{10}=12\Rightarrow\ x=12\times10=120\)
Hence, there are 120 boats in marina.
There are 120 boats in the marine
Let the total boats in the marina be "x"
If five-sixths of the boats in the marina are white, 2/5 of the remaining boats are blue and the remaining are red, hence the fraction that are red is expressed as:
Fraction that are red = 1 - (5/6+1/15)
Fraction that are red = 1 - (25+2/30)
Fraction that are red = 1 - (27/30)
Fraction that are red = 3/30 = 1/10
Since there are 12 red boats, the total boat is calculated as:
1/10 of x = 12
x = 10 * 12
x = 120
Hence there are 120 boats in the marine
Learn more on ratios here: https://brainly.com/question/2914376